A small riddle

[.†.MikeL.†.]

My Father told me a riddle not very hard but not very easy too(sorry if my english are not very good):p

One day a Doctor asked a Farmer nearby:
Doctor:How many sheep do you have my good man(he thought the Farmer doesn't know how to count):p
And the farmer answered.
Farmer:If I had as many as I have and the half of what I have and 5 and 50 I would make them 100:cool:
Then the Doctor turned away and left like a wet bird.:p

How many sheep the Farmer has?;)
Do you know the answer?:D

[Yavanna]

He has 15 sheeps... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

[Sword guy]

90§lehrer

[.†.MikeL.†.]

He has 15 sheeps... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

The first time I had said the same:D
Sorry wrong:)


90§lehrer

Yes that is really a scientific answer§xlol §xlol §xlol

I see that you have good taste of humor even your avatar shows that:D

[Sword guy]

30..... my mistake....:D

[.†.MikeL.†.]

30..... my mistake....:D

Wrong once again:D

[Yavanna]

Hmmm... no... maybe you didn't post the riddle right... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

If I had as many as I have ( x + x) and the half of what I have ( 1/2 * ( x + x ) and 5 and 50 I would make them 100.


x + x + 1/2 * ( x + x ) + 5 + 50 = 100

3 * x + 55 = 100

3 * x = 45 => x = 15

http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

[.†.MikeL.†.]

Hmmm... no... maybe you didn't post the riddle right... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

If I had as many as I have ( x + x) and the half of what I have ( 1/2 * ( x + x ) and 5 and 50 I would make them 100.


x + x + 1/2 * ( x + x ) + 5 + 50 = 100

3 * x + 55 = 100

3 + x = 45 => x = 15

http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

Nop try harder:)
It is somehow tricky you know(IMO riddle);)

[DeadlyArrow]

@yavanna
i think "half of what i have" would be 1/2*x, not x+x

edit - 18

[Yavanna]

Nop try harder:)
It is somehow tricky you know(IMO riddle);)

Look... I've been doing exercises like this one since I was in 4th grade...

It's not my fault if it's some sort of weird riddle... I just solved the problem... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

And no, I won't try harder, because this is the answer :p ... if I would find this problem in a math book, this would be the answer...

Or maybe I just can't understand what you wrote... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif



@yavanna
i think "half of what i have" would be 1/2*x, not x+x

Hmmm... no... because at that moment he has x + x...

[rockfest]

18. at least this is what i think :p

//Edit : damn, deadly was faster ;)

[.†.MikeL.†.]

Look... I've been doing exercises like this one since I was in 4th grade...

It's not my fault if it's some sort of weird riddle... I just solved the problem... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

And no, I won't try harder, because this is the answer :p ... if I would find this problem in a math book, this would be the answer...

Or maybe I just can't understand what you wrote... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

Don't be mad with me:(
Acually it is not a story it really happened:D
I had really hard time to find out the small trick in it(I said it is tricky):p and my father was loughing with me but when I answered HE turned away like a wet bird:D

EDIT

18. at least this is what i think :p

//Edit : damn, deadly was faster ;)

Yep you are really something ehh?:)
But I see that some others answered too now I AM the wet bird:D

[Yavanna]

@MikeL : I am not angry at anyone... the indifferent smiley is cool... that's why I use it...
But when I am serious, I just don't use any kind of smiley in my post...
You will know when I am serious...

@rockfest: We had a similar problem when we had the exam 4 years ago... just try to remeber...
And the people who only said 15% from x lost 1 point at that exam... :rolleyes:

[.†.MikeL.†.]

@MikeL : I am not angry at anyone... the indifferent smiley is cool... that's why I use it...
But when I am serious, I just don't use any kind of smiley in my post...
You will know when I am serious...

@rockfest: We had a similar problem when we had the exam 4 years ago... just try to remeber...
And the people who only said 15% from x lost 1 point at that exam... :rolleyes:

Hehe now I understand:)
You saw the answer right 18 sheep;)
A quit clever Farmer don't you think (I can't give name):D

[Yavanna]

The answer is still 15 in my opinion...

You said:

If I had as many as I have and the half of what I have ( this is a present tense ) and 5 and 50 I would make them 100


The answer would be 18 only in this case:

If I had as many as I have ( this is a present tense ) and the half of what I had and 5 and 50 I would make them 100

[rockfest]

@Yavanna actually the problem is like this :
If i would have as many as i have and the half of what i have(the real number not the "if" one) ;)

[thegame_]

look yavanna it's like this
If I had (past tense) as many as I have(present tense) (18 + 18 = 36) and the half of what I have (18 * 1/2 = 9 so.. 36 + 9 = 45) and 5 (45 + 5 = 50) and 50 ( 50 + 50 = 100 :D ) would make them 100.

hope you understand my crappy way of explaining :D §lehrer

[.†.MikeL.†.]

Isn't it a nice riddle.........................well mathimatic riddle:D

I think I have some more riddles for you but not now;)

See Ya!!!!!!

[Yavanna]

look yavanna it's like this
If I had (past tense) as many as I have(present tense) (18 + 18 = 36) and the half of what I have (18 * 1/2 = 9 so.. 36 + 9 = 45) and 5 (45 + 5 = 50) and 50 ( 50 + 50 = 100 :D ) would make them 100.

hope you understand my crappy way of explaining :D §lehrer
Your explination is good, but you also have to admit that I might be right...

Like I said... half of what I have... at the present moment, after adding x to my number, I have 2*x

Just forget it... http://i9.photobucket.com/albums/a87/yavanna_1986/16x16_smiley-indifferent.gif

[Godcrusher]

sorry but i hate math in a very strange way....so well done deadly:)

[Nikolaa]

man i don't understand what is ritten up there(i understand but when i ride it i get comfused:confused: )

[DeadlyArrow]

oki, if anybody would understand, i have a small riddle too;)

imagine 4 matches placed like that VII - seven (romenic), move one match to make one
hint - use maths

[WernerTWC]

oki, if anybody would understand, i have a small riddle too;)

imagine 4 matches placed like that VII - seven (romenic), move one match to make one
hint - use maths
Ignoring that hint ;) :D :p :
The one i moved away is that one.

[thegame_]

oki, if anybody would understand, i have a small riddle too;)

imagine 4 matches placed like that VII - seven (romenic), move one match to make one
hint - use maths hmmm... well i dunno the right answer
but i have an alternative one move the last I on top to make the V with a roatated I look like a radical so radical of 1 is one :D

this is some kind of easteregg of this riddle :D
don't think you understood :)

[DeadlyArrow]

hmmm... well i dunno the right answer
but i have an alternative one move the last I on top to make the V with a roatated I look like a radical so radical of 1 is one :D

this is some kind of easteregg of this riddle :D
don't think you understood :)

totally right:D

the same one is with cow
http://img100.imageshack.us/img100/1510/cow5lx.jpg (http://imageshack.us)

imagine that the bomb is flying towards it! you can move 2 matches to save it:D

[.†.MikeL.†.]

oki, if anybody would understand, i have a small riddle too;)

imagine 4 matches placed like that VII - seven (romenic), move one match to make one
hint - use maths

It's not a bad one:dup:
If someone else know any other riddle I would really like to see it(not from games of course);)
I don't know why but I really like riddles somehow:p

[ArmyOfOne]

oki, if anybody would understand, i have a small riddle too;)

imagine 4 matches placed like that VII - seven (romenic), move one match to make one
hint - use maths

I was thinking:

Just tilt the first "I" counterclockwise to make it sort of VV .... or W. (I cant make the last I stay)
That way, its "one" piece.

W/e lol

[SirPaladin]

A new riddle:
A hotel has 10 floors, each floor has 6 apartments and each apartment has 4 rooms.
What`s the owner`s age?

[Godcrusher]

that's not possible...or i just suck at this

[Colonelu]

A new riddle:
A hotel has 10 floors, each floor has 6 apartments and each apartment has 4 rooms.
What`s the owner`s age?

I think its 64

[SirPaladin]

I think its 64
LOL
It`s a joke, don`t you see? HIS AGE :rolleyes:
And the building has 240 apartments BTW

[thegame_]

the same one is with cow
http://img100.imageshack.us/img100/1510/cow5lx.jpg (http://imageshack.us)

imagine that the bomb is flying towards it! you can move 2 matches to save it:D i dunno... :confused:

A new riddle:
A hotel has 10 floors, each floor has 6 apartments and each apartment has 4 rooms.
What`s the owner`s age?man... put real ones in here... ;)
although it was fun to see how they got tricked :D

if anyone has others... post them :)

[Colonelu]

And the building has 240 apartments BTW

I know that the building has 240 apartements but how the f*** can a man have 240 :rolleyes:

[fatfish]

i have a riddle.....

if 1 candle burns in 1 hour, 3 candles (alike) will burn in how many hours?

[DeadlyArrow]

i have a riddle.....

if 1 candle burns in 1 hour, 3 candles (alike) will burn in how many hours?
sure, if they burn together, they will burn in 1 hour too:D

[Godcrusher]

i have a riddle.....

if 1 candle burns in 1 hour, 3 candles (alike) will burn in how many hours?


i got the same one on logical test some years ago...one hour:)

[SirPaladin]

i have a riddle.....

if 1 candle burns in 1 hour, 3 candles (alike) will burn in how many hours?
Yeah, it`s old, but nice.
Logic test (translated in English by SirPaladin :p)

The RF has 3C
The Romanian flag has 3 colors

The S has 8l
A D is N12
The W has 7D (easy one)
The T has 3W
The C has 9L
The FT has 11P
The CP has 52 C (EJ) (crazy one)

And others ;)

[thegame_]

The RF has 3C
The Romanian flag has 3 colors

The S has 8l
A D is N12
The W has 7D (easy one)
The T has 3W
The C has 9L
The FT has 11P
The CP has 52 C (EJ) (crazy one)

And others ;) this is not that easy... i could say MH has 11F you'll never know unless you put it

The T has 3W - tricycle has 3 wheels maybe
the rest dunno and don't really have time to think so much at everyone... hints maybe?

[SirPaladin]

easy one: The week has 7 days
Think at EVERYTHING ;) I can`t give hints. It wouldn`t be a challenge anymore.

[thegame_]

so i got 4 by now :)

a D has N12 - a dozen has N12 (does "N" mean smth or just a symbol ;) )
the W has 7D - week has 7 days
the T has 3W - tricycle has 3 wheels
the FT has 11P - football team has 11 players

[fatfish]

Einstein's test...

--Einstein give us a puzzle like this, for he stressed examining assumptions, and once wrote: "The important thing is to not stop questioning."
--Facts:
-There are 5 houses in 5 different colours
-In each house lives a person with a different nationality..
-These 5 owners drink a certain beverage, smoke a certain brand of cigar and keep a certain pet.
-No owners have the same pet, smoke the same brand of cigar or drink the same drink.

--Hints:
1. The Brit lives in a red house.
2. The Swede keeps dogs as pets.
3. The Dane drinks tea.
4. The green house is on the left of the white house.
5. The green house owner drinks coffee.
6. The person who smokes Pall Mall rears birds.
7. The owner of the yellow house smokes Dunhill.
8. The man living in the house right in the centre drinks milk.
9. The Norwegian lives in the first house.
10. The man who smokes Blend lives next to the one who keeps cats.
11. The man who keeps horses lives next to the man who smokes Dunhill.
12. The owner who smokes Blue Master drinks beer.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The man who smokes Blend has a neighbour who drinks water.

The question for the Einstein test is ... WHO KEEPS THE FISH?


P.S. i pasted it directly from the internet so i wont have to translat it :D
the thin is thet if u resolve the test and post the answer th others wont know how to reach the response... good luck :cool:

[thegame_]

The question for the Einstein test is ... WHO KEEPS THE FISH?


P.S. i pasted it directly from the internet so i wont have to translat it :D
the thin is thet if u resolve the test and post the answer th others wont know how to reach the response... good luck :cool: the german keeps the fish ;)
it was quite hard to find out... :) but it's a nice test :cool:
should i say how i found out §lehrer ?


i have one but is damn hard... wich number is next?
1
11
21
1211
111221
?


anyway, i want more riddlez guyz! :p

[ArmyOfOne]

The C has 9L

The Cat has Nine Lives

[ArmyOfOne]

For the Einstein Problem:

I solved it MECHANICALLY then I looked it up online and theres a so-called "real" answer to this question. Also, some site claimed that Einstein said 98% of the people in this world cant solve it. Well I solved it... but I guess not for the "real" answer. I could tell you the real answer but it would spoil the good riddle.

Mechincally, the answer is The German keeps the Fish.

So if you want to see the real answer:
http://www.amazeingart.com/fun/einstein-quiz-answer.html

[SirPaladin]

LOOK:

A man reaches a crossroad. There, he meets 3 men: A, B and C
Man: Are you a liar or you say the truth?
'A' says something, and the man doesn`t understand.
Man: What did you say?
B: He said he`s a liar.
C: No! He didn`t say that!

Question: does 'C' say the truth or not?

[R3l!3f_CZ]

LOOK:
A man reaches a crossroad. There, he meets 3 men: A, B and C
Man: Are you a liar or you say the truth?
'A' says something, and the man doesn`t understand.
Man: What did you say?
B: He said he`s a liar.
C: No! He didn`t say that!
Question: does 'C' say the truth or not?
He say the truth, because if A would say he's liar, C would be another liar and that's cannot be:D :D :D

[SirPaladin]

It`s not logical. It`s true, but I want a good explanation.

[R3l!3f_CZ]

It`s not logical. It`s true, but I want a good explanation.
Hey,§burn §burn
I've already said that.....§burn §burn §burn
So if A said he's a liar, then B would speak the truth and C would be another liar;) ;) ;)
And if A said he's not a liar, then B would be a liar and C spoke the truth...;) ;)

[SirPaladin]

Hey,§burn §burn
I've already said that.....§burn §burn §burn
So if A said he's a liar, then B would speak the truth and C would be another liar;) ;) ;)
And if A said he's not a liar, then B would be a liar and C spoke the truth...;) ;)
Look, it`s easy!
I`m a liar ;)
Get it?

[SkySaint]

How about this one.... :cool:

A wanderer meets a strange man who says to him:
You may say somehing to me but if the next thing you say (and you must say something) is a lie "i will kill you with my spell" and if you speak the truth then "i will kill you with my sword"...

so what does the wanderer have to say to stay alive?

[Colonelu]

How about this one.... :cool:

A wanderer meets a strange man who says to him:
You may say somehing to me but if the next thing you say (and you must say something) is a lie "i will kill you with my spell" and if you speak the truth then "i will kill you with my sword"...

so what does the wanderer have to say to stay alive?

Nothing :D

[SirPaladin]

How about this one.... :cool:

A wanderer meets a strange man who says to him:
You may say somehing to me but if the next thing you say (and you must say something) is a lie "i will kill you with my spell" and if you speak the truth then "i will kill you with my sword"...

so what does the wanderer have to say to stay alive?
I live in the USA :D
It`s a lie, and spells don`t exist. :p

[ArmyOfOne]

How about this one.... :cool:

A wanderer meets a strange man who says to him:
You may say somehing to me but if the next thing you say (and you must say something) is a lie "i will kill you with my spell" and if you speak the truth then "i will kill you with my sword"...

so what does the wanderer have to say to stay alive?

you dont have to say anything at all in the first place. it says you MAY say something. just walk away lol

[fatfish]

there is another riddle....


tomorrow i have an exam and today i've learned 0 ... ok there r 2 posibilitys:

1. go to the exam, do nothing and pray that i wont make a foul of myself...


OR

2. go to the exam, do nothing, pay the profesor 70$ and pray that i wont make a foul of myself and he'll take the money...

if u know the answer pls post here.... 10q

[Colonelu]

The second answer :D

[SirPaladin]

there is another riddle....


tomorrow i have an exam and today i've learned 0 ... ok there r 2 posibilitys:

1. go to the exam, do nothing and pray that i wont make a foul of myself...


OR

2. go to the exam, do nothing, pay the profesor 70$ and pray that i wont make a foul of myself and he'll take the money...

if u know the answer pls post here.... 10q

I doubt that there`s a CORRECT answer.
I`d choose the first one... yeah, I`m a goodie-shoes :p
But the second one... If the exam is so important, maybe the 70$ is worth it :D

But naaaah, only a loser would learn 0% for an important exam.

[fatfish]

i chosed A #1 and.... wahoo... i passed
well SirPaladin... looks likt the loser takes it all ;)

[fatfish]

i will double post!

the strangest thing.... :D
the theory of 4=3

a+b=c => 4a-3a+4b-3b=4c-3c => 4a+4b-4c=3a+3b-3c =>
=> 4(a+b-c)=3(a+b-c) => 4=3

unbeliveble isn't it!!! :D

[Colonelu]

i will double post!

the strangest thing.... :D
the theory of 4=3

a+b=c => 4a-3a+4b-3b=4c-3c => 4a+4b-4c=3a+3b-3c =>
=> 4(a+b-c)=3(a+b-c) => 4=3

unbeliveble isn't it!!! :D

Maths just suck :D

[SkySaint]

How about this one.... :cool:

A wanderer meets a strange man who says to him:
You may say somehing to me but if the next thing you say (and you must say something) is a lie "i will kill you with my spell" and if you speak the truth then "i will kill you with my sword"...

so what does the wanderer have to say to stay alive?

ok guys here's how it goes and i must say that i was maybe wrong to put "MAY" say something but anywho look:

You just say: "You will kill me with your spell"

...think about it :D ...

[SirPaladin]

i will double post!

the strangest thing.... :D
the theory of 4=3

a+b=c => 4a-3a+4b-3b=4c-3c => 4a+4b-4c=3a+3b-3c =>
=> 4(a+b-c)=3(a+b-c) => 4=3

unbeliveble isn't it!!! :D

Well, it isn`t a theory. Why?

4a-3a+4b-3b=4c-3c
Hmmm, so the bold part=4 and the underlined=3. It`s a inequation, it`s NOT true, so it isn`t something provable §lehrer
I`m not a maths freak, I don`t even like maths (LOL) but I took it logically.



P.S. I`m such a spammy Schwertmeister :p

[WernerTWC]

the theory of 4=3

a+b=c => 4a-3a+4b-3b=4c-3c => 4a+4b-4c=3a+3b-3c =>
=> 4(a+b-c)=3(a+b-c) => 4=3

unbeliveble isn't it!!! :D
I think it's just wrong, you cannot say 4a-3a, it should be (4a-3a). (IMHO)

[one-cool]

I think it's just wrong, you cannot say 4a-3a, it should be (4a-3a). (IMHO)
and that changes nothing^^

btw:

your mistake is here:

a+b=c => 4a-3a+4b-3b=4c-3c

you can't come from the first to the second step. these two are different things ;)

[Khaos_Knight]

ok guys here's how it goes and i must say that i was maybe wrong to put "MAY" say something but anywho look:

You just say: "You will kill me with your spell"

...think about it :D ...

I get it, since that is a lie, he will kill you with the spell, but then its true, so he will kill you with his sword, but then its a lie and then his head will explode.

[fatfish]

and that changes nothing^^

btw:

your mistake is here:

a+b=c => 4a-3a+4b-3b=4c-3c

you can't come from the first to the second step. these two are different things ;)


as long as it's an equality i can change the therms how ever i want as long as the resunt is the same... so what u said is wrong

@SirPaladin.... ur right, ur not a maths freak, so look again
@WernerTWC... thiz r opperations of the sama degree so thiz "( )" r not necesary

the mistake is still there... annalize it well ;)
it's easy

[thegame_]

the strangest thing.... :D
the theory of 4=3

a+b=c => 4a-3a+4b-3b=4c-3c => 4a+4b-4c=3a+3b-3c =>
=> 4(a+b-c)=3(a+b-c) => 4=3 the thing is thats not 4=3, it's in fact 0=0 ;) try replacing a, b and c with numbers to understand cause (a+b-c) = 0 so 4*0=3*0 ;) so 0=0 §lehrer

[fatfish]

the thing is thats not 4=3, it's in fact 0=0 ;) try replacing a, b and c with numbers to understand cause (a+b-c) = 0 so 4*0=3*0 ;) so 0=0 §lehrer


§klatsch BRAVO u earned a 10 on math from me :D

[Kpau]

the answer to the 4=3 problem is such : in mathemathics you cannot divide by 0 .simplyfying the ecuation by a+b-c is simplyfying it by 0 since a+b=c.You can make many infinite more numbers equal if you use this falsity.
the answer to the first post is 30.Read between the lines people :).

[Fnoop]

Good riddle...I love riddles :D

[Fnoop]

Just a thought ;) I wonder if there is someone here who could tell me how to put 10 coins in five rows of four (there must be four coins in each row and five such rows must exhist). It isn't easy but not impossible either ;) if anyone thinks he knows the answer, he can use @ to show how he put the coins.

Exhample:
@
@@@@
@@@@
@

Good luck :rolleyes:

[Onisuzume]

How about getting more coins?

[ArmyOfOne]

@
@
@
@@@@@
@
@

I hope it shows up clearly..... The vertical line has 3 rows of four coins while the horizontal line has 2 rows of four. That makes 5 rows of four coins!!

:D

[Kpau]

Could you reformulate please..because it doesn't make any sense.If you think mathemathical or matrix-ional 5 rows of 4 means 20 elements.So reformulate please or rescue me from my imbecility.
Anyhow i will give you a very simple formulated yet difficult problem :

Demonstrate that every even number can be written as the sum of 2 prime numbers.

[fatfish]

in mathemathics you cannot divide by 0
this the best answer to this riddle... bravo Kpau

here is another one...

3+3:3=?

[rekinu]

I merged the Coin Challenge thread with this one, because it's the same subject :)


@
@
@
@@@@@
@
@

I hope it shows up clearly..... The vertical line has 3 rows of four coins while the horizontal line has 2 rows of four. That makes 5 rows of four coins!!

I don't get it....:confused:


here is another one...

3+3:3=?
4 ?

[Kpau]

Hardly any mathemathical riddle to this one :) , 4 is the answer

[ArmyOfOne]

I merged the Coin Challenge thread with this one, because it's the same subject :)


I don't get it....:confused:




@
@
@
@@@@@
@
@

1st Row:
Count the first four down from the top. (vertical line)

2nd Row:
Count the 2nd four down (vertical line)

3rd Row:
Count the last 4 from the bottom up (vertical line)

4rd Row:
The first four in the horizontal Line

5th Row:
The four coins counting from the right of the Horizontal Line

[rekinu]

well, now I understand, but you can't say that a vertical line is a row. It's a column :D And what Fnoop wants, it's impossible, you need more coins -_-

[Kpau]

The most obvious answer to this badly formulated riddle is this one.
@
@
@
@
@
@
@
@
@
@
Also it conatins 7 columns of 4 elements each heheheheh :).

[Fnoop]

well, now I understand, but you can't say that a vertical line is a row. It's a column :D And what Fnoop wants, it's impossible, you need more coins -_-
It isn't impossible at all, if I would show you, you would agree with me :)
No, things like this:
@
@
@
@
@
@
@
@
@
@
are not the correct answer. You don't have five rows of four but one row of ten. It CAN be done, it isn't a trick ;)

[Kpau]

The way you formulated the problem my answer is correct Fnoop.You should give some more information on the parametres of the problem like no 2 rows my have more then one common element.Without those parametres there are 7 rows of 4 elements each in a 10 element column.So shoot the parameters .Also your example :

Exhample:
@
@@@@
@@@@
@
is not correct in regards with the parameters you have given.There are only 3 rows.You must keep in mind that an example is a correct answer by definition.

[Fnoop]

I don't know how else to formulate, however you take it, this:
@@@@@@@@@@
is ONE row and not seven. You must build rows like these:
@@@@@
@@@@@
@@

here, there are two rows of 5 coins, 2 rows of 3 and 2 rows of 2 coins.

[Lazor]

I found an interesting riddle yesterday and I did solved it alone. I like these "brain teasers" so here you are:

"How old is Alex ?" A friend asked my one day
"Alex? Well.. 18 years ago he had three time his son's age"
"Yeah but NOW he is twice older than his son"
"Yep, and that's why it's not that hard to find his, and his son's age"

So? How old are they??

[Omid-]

NONONONONONONONONO!!!! My brother annoys me too much with these riddles, now they are here to??!!?!! HOLY CRAP! If someone can answer that 1 i have another 1 that is superiourly annoying:(

[Danto]

I hate those riddles :D
Here is a kinda tricky riddle :D
You are the owner of a bus.You move from point A to point B with 200 km.After 2 hours you lower the speed to 60 km.How old is the bus driver?

[Powaz]

15 years old.Easy.
Lazor's riddle is much harder.
Okay I get it.Now the son is 36 years old and Alex is 72 years old.
Ups got 54 + 18 = 62 :D stupid mistake.It's 72.

[nirolF]

Alex 72
Son 36
Just a simple system of two linear equations\

Edit: Here is a harder one.
You have 10 bags. You must put a certain number of coins in each of the bag so you can pay any sum from 1 to 1000 without opening any of the bag, but just by combining the bags

[Cylon13]

100 coins in each bag making it 1000 if combined. :D

[nirolF]

you must be able to obtain any value between 1 and 1000 and you don't have to use all the bags at once.
You have only 10 possibilities with your solution. 990 others different values needed :D

[Lazor]

That's impossible! I can do it with 12 bags not 10

[nirolF]

Don't underestimate the power of numbers ;)

[Danto]

what about this shit :D
So a boat can only carry 90 kilos
Man 60
Woman 60
Girl 30
Boy 30
So a woman cant be left with a boy and man cant be left with a girl.There must be 2 people who drive the boat.But adults can only drive it.
So use paint or give a detailed explanation :D

[Lazor]

Don't underestimate the power of numbers

I don't underestimate them but I still can't solve it :D:D Anyway I'll think about it ;) 12 bags is the only way I've found till now

[rekinu]

you must be able to obtain any value between 1 and 1000 and you don't have to use all the bags at once.
You have only 10 possibilities with your solution. 990 others different values needed :D

1 2 4 8 16 32 64 128 256 512

And you can pay any sum from 1 to 1000+ :)

[nirolF]

I don't underestimate them but I still can't solve it :D:D Anyway I'll think about it ;) 12 bags is the only way I've found till now

By power I do not mean potential or capability. think figuratively.
No more that 10 needed. You can obtain even a greater number of values just by using those 10 bags. if I say that number it might be to obvious


1 2 4 8 16 32 64 128 256 512

And you can pay any sum from 1 to 1000+

That's it! good job

[Danutz_plusplus]

That's it! good job

Can there be more solutions?

Because I think 1 2 4 8 16 32 64 128 256 489 also work.

[nirolF]

guess so. on the last bag you can put any number between 489 and 512. But you can obtain those numbers using the others bags and since the catch of the riddle are the powers of the number 2 from 0 to 9, 512 should be the answer

[Danutz_plusplus]

guess so. on the last bag you can put any number between 489 and 512. But you can obtain those numbers using the others bags and since the catch of the riddle are the powers of the number 2 from 0 to 9, 512 should be the answer

Not necessarily. You can determine those numbers without even touching the powers of 2 thingy.:p But it's pretty hard to do by hand. Easiest way would be to write an app that passes through numbers from 1 to 1000 and for each one determine if it can be generated by using the previously added numbers in a vector. If the number cannot be generated using the other numbers you add it to the previously mentioned vector. And you keep adding until you reach 1000. And that should get you the vector that ends with 489.

For the testing part(if it can be generated using the previously added numbers) you can use a backtracking algorithm and check all possible combinations if they add up.

But it's a whole lotta work just to get to those numbers.:p So maybe the powers of 2 thingy is key.:p

[nirolF]

You can determine those numbers without even touching the powers of 2 thingy.:p But it's pretty hard to do by hand. Easiest way would be to write an app that passes through numbers from 1 to 1000 and for each one determine if it can be generated by using the previously added numbers in a vector. If the number cannot be generated using the other numbers you add it to the previously mentioned vector....

This is not a pure programming problem, just math. The algorithm you explain is correct (actualy this is how I solved it on paper). Using it you end up with the same powers of 2 and no other numbers (except the last one). There are no other solutions.
When solving it on paper you easily see the pattern and deduce the powers of 2 solution. Then you just have to verify some base cases to see it's correct.

To have 1 you need 1 = 2^0
To have 2 you need 2 = 2^1(as you can not use 2 bags with 1)
To have 3 you use 1+2
To have 4 you need 4 = 2^2
To have 5 you use 4+1
To have 6 you use 4+2
To have 7 you use 4+2+1
To have 8 you need 8 = 2^3
and so one..
You can see that you can generate any number using the power of 2 numbers smaller than the curent number.
Ex: for any number between 16 and 31 I just need the powers of 2 from 0(1) to 4 (16); for any number between 256 and 511 I only need powers of 2 till 9(512).
I think you can verify this using induction

[Danutz_plusplus]

This is not a pure programming problem, just math. The algorithm you explain is correct (actualy this is how I solved it on paper). Using it you end up with the same powers of 2 and no other numbers (except the last one). There are no other solutions.
When solving it on paper you easily see the pattern and deduce the powers of 2 solution. Then you just have to verify some base cases to see it's correct.


I'd even go as far as to say that every programming problem is a math problem mainly. And yeah, I can see your point. :) Actually, I just wanted to brag with that algorithm.:p

[.†.MikeL.†.]

Oh damn I had forgotten about this thread and it was damn entertaining reading (especially) the first pages again, it was the only time I had ever "beat" (if you'll allow me) Rox at maths :p

My english look creppy >_>

[Khaled]

If you look attentive, there are like 2 generations of posters in this thread :p
Only rekinu posted both in the past and in the present.

[rekinu]

Only rekinu posted both in the past and in the present.
What about the guy above you ? ;)

Anyone has some more riddles ?

[.†.MikeL.†.]

"I see without seeing and I'm wandering the darkness, dark is as bright as sunlight to me... what am I?..."

Easy, it's from a movie :p



Only rekinu posted both in the past and in the present.

Aham! :o

[Khaled]

Aham! :o

Oh..right..hehe :grinundwe

[.†.MikeL.†.]

"I see without seeing and I'm wandering the darkness, dark is as bright as sunlight to me... what am I?..."

No one can solve it? O_o

[Danto]

here is another: Ivan tells himself that tomorow at 7 o'clock he will do gymnasticks if there is a sun.The next day its 7.15 and there is a sun.Will he do as planned?Why?

[WarTom]

here is another: Ivan tells himself that tomorow at 7 o'clock he will do gymnasticks if there is a sun.The next day its 7.15 and there is a sun.Will he do as planned?Why?

No. If he would, you said something wrong in your translation from Bulgarian.

Day 1: 7 o'clock it could be 07:00, or 19:00 but in the way you represent it that would be irrelevant.

Day 2: 07:15 in the morning, there is sun. He is 15 minutes too late. Unless he already did the gymnastics, in which case the riddle was random.

[Danto]

Well I meant he woke up in 7.15 instead of 7.00.When he wakes up he starts doing gymnastics.So the riddle is like this. ;)

[em93]

22 ? $zuck

[WernerTWC]

22 ? $zuck

Pfff, 42 is the answer! :o §lehrer :p

[.†.MikeL.†.]

Pfff, 42 is the answer! :o §lehrer :p

Wrong, it's 52!! :o